A B C D E F G H I J K L M N O P Q R S T U V W X Y Z

How did JJ Thomson discover the e/m ratio?

Best Answers

The first is the experiment of Joseph John Thomson, who first demonstrated that atoms are actually composed of aggregates of charged particles. .... where $E$ is the magnitude of the electric field. Solving for the charge-to-mass ratio, we have $q/M = g/E$ . read more

J.J. Thomson's experiment and the charge-to-mass ratio of the electron The first is the experiment of Joseph John Thomson, who first demonstrated that atoms are actually composed of aggregates of charged particles. read more

Thomson found that cathode rays always had the same e/m ratio, no matter what metals were used for the cathodes and no matter what gas was used in the tubes. Kaufmann concluded that the hypothesis that cathode rays were particles was inconsistent with this result. read more

Experiment 3. The Thomson experiment. Thomson did not know the value of e. Since he did not know e, he could not determine vx, and thus could not use the deflections in B and E separately. However, he could eliminate vx as a variable, thereby obtaining e/m for the electron, by measuring the value of B which just cancelled the deflection by E. read more

Encyclopedia Research

Wikipedia:

Related Types

Related Question Categories