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What is the average of the first n positive even numbers?

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We can start with the sum of the first n positive integers. It's (n(n+1))/2. You can think of the sum of the first n positive even numbers as twice the sum of the first n positive number. This would make it n(n+1) (from the first formula). The average of these numbers would be n(n+1)/n or just n+1. read more

You can think of the sum of the first n positive even numbers as twice the sum of the first n positive number. This would make it n(n+1) (from the first formula) The average of these numbers would be n(n+1)/n or just n+1. read more

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