What is the probability that a non leap year has 52 Sundays?

A non leap year has 365 days, so, we can have 52 weeks (52 x 7=364 days) and we're left with one day extra (365–364=1). This day can be any one of the seven different days and since we already had 52 Sundays because we already completed 52 weeks, we don't want this extra day to be a Sunday. So, the no. read more

For the Question "Find the probability that a leap year has 53 Sundays". The Solution goes : For 53 Sundays, we proceed as: $\frac{366}{7} = 52.28$; So we can be sure that there are 52 Sundays, now the only question is of the 1 Sunday. So $7\cdot 52 = 364$. Therefore the remaining 2 days (366-364) decide the probability of being a Sunday. read more

Normal year has 52 weeks (365/7) + 1 extra day ie. 52 Sundays + 1 day which can be any of the seven days So probability of 53 Sundays === Probability of that day being a sunday = 1/7 OR The year MUST start on a Sunday, so you have only one favorable chance out of a total of 7 possibilities - a probability of 1/7. read more

Leap years in the popularly used Gregorian calendar add one day to the end of February. The probability that a leap year will have 53 Sundays is one out of seven. There’s one more day-of-the-week than side-of-the-die, but this is still a good illustration. read more