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What is the sum of first [math]n[/math] even numbers?

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Sum of first [math]n[/math] even numbers is [math]n(n + 1)[/math]. Proof: Let [math]S[/math] be the sum of first [math]n[/math] even numbers. read more

The sum of the first n even numbers is bigger than the sum of the first n odd numbers, because the first even number (2) is bigger than the first odd number (1) and this pattern continues (4 is bigger than 3). read more

Sum of first [math]n[/math] even numbers is [math]n(n + 1)[/math]. Proof: Let [math]S[/math] be the sum of first [math]n[/math] even numbers. [math]S = 2 + 4 + \dots + 2n[/math] [math]S = 2n + 2(n-1) + \dots + 2[/math] Adding both of these equations: [math]2S = (2n + 2)n[/math] [math]S = n(n + 1)[/math] Q.E.D. read more

The sum of the first 100 even numbers is 10,100. This is calculated by taking the sum of the first 100 numbers, which is 5,050, and multiplying by 2. To find the total of the first 100 numbers, multiply 50 by 101. read more

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